Nov 6, 2020 · This question was asked in my linear algebra quiz previous year exam and I was unable to solve it. Let V be an inner ( in question it's written integer , but i think he means inner) product …

Nov 5, 2015 · So I was working through this review question and got stumped. My answer isn't completely orthogonal to matrices in a certain subspace, so it's incorrect. The question is: Let S be a …

Jun 21, 2025 · Continue to help good content that is interesting, well-researched, and useful, rise to the top! To gain full voting privileges,

Nov 13, 2020 · 1 Let $W$ be a subspace of $\mathbb {R}^n$. We know that $W^\perp$ is also a vector subspace of $\mathbb {R}^n$. How can I show that $\dim W + \dim W^\perp = n$? I know that for a …

Jun 6, 2021 · I'm trying to prove the following: Show that the annihilator $M^\perp$ of a set $M \neq \emptyset$ in an inner product space X is a closed subspace of X. Next is the ...

Apr 1, 2017 · What is the meaning of superscript $\perp$ for a vector space Ask Question Asked 14 years, 7 months ago Modified 8 years, 8 months ago

Jul 10, 2017 · Let $V$ be a finite dimensional vector space over the field $K$, with a non-degenerate scalar product. Let $W$ be a subspace. Show that $W^{\\perp\\perp}=W$. I have ...

Jul 9, 2013 · Why is $W^\perp = null (A)$ I dont like learning these kinds fo things, is there a way to understand this? WHY is this the case, why do they specifically let A use $w_1$ and $w_2$ as the …

Mar 25, 2015 · Would a contradiction showing a vector $\vec {v}\in \text {im } (A^T), \notin (\text {ker }A)^\perp$ even be possible? My intuition says yes but the definitions seem to leave no exception.

Mar 29, 2020 · W is a linear subspace in $R^n$. If $B_1$ is an orthogonal basis for W and $B_2$ is an orthogonal basis for $W^\perp$, how I prove that the union of $B_1$ and $B_2 ...